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Q.1%3A%20A%20particle%20moves%20in%20the%20x-y%20plane%20under%20the%20influence%20of%20a%20force%20such%20that%20the%20linear%20momentum%20Is%20P%28t%29%20%3D%20A%20%5B%20%EE%20cos%20kt%20-%20%u0135%20sin%20kt%20%5D%20Where%20A%20and%20k%20are%20constants.%26nbsp%3B

The%20angle%20in%20degrees%20between%20force%20and%20momentum%20is_________.%26nbsp%3B

Answer%3A%2090%26nbsp%3B

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Q.2%3A%20A%20power%20line%20lies%20along%20the%20east-west%20direction%20and%20carries%20a%20current%20of%2010%20A.%20The%20force%20per%20meter%20due%20to%20earth%27s%20magnetic%20field%20of%2010-4%20T%20is%2010-X%20N/m.%26nbsp%3B

The%20value%20of%20x%20is_____________.%26nbsp%3B

Answer%3A%203%26nbsp%3B

Q.3%3A%20The%20sun%27s%20disc%20subtends%20an%20angle%20of%2010-2%20rad%20at%20the%20earth.%20The%20radius%20of%20curvature%20%28in%20meters%29%20of%20the%20mirror%20which%20will%20produce%20on%20a%20screen%20an%20image%20of%20the%20sun%202%20cm%20in%20diameter%20is____________.%26nbsp%3B

Answer%3A%204%26nbsp%3B

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Q.4%3A%20The%20binding%20energy%20of%20deuteron%20%281H%202%29%20is%201.15%20MeV%20per%20nucleon%20and%20an%20alpha%20particle%20%28%202He4%20%29%20has%20a%20binding%20energy%20of%207.1%20MeV%20per%20nucleon.%26nbsp%3B

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Answer%3A%2023.8%26nbsp%3B

Q.5%3A%20Light%20of%20wavelength%200.6%20mm%20from%20a%20sodium%20lamp%20falls%20on%20a%20photocell%20and%20causes%20the%20emission%20of%20photoelectrons%20for%20which%20the%20stopping%20potential%20is%200.5%20V.%20With%20light%20of%20wavelength%200.4%20mm%20from%20a%20mercury%20lamp%20the%20stopping%20potential%20is%201.5%20V.%26nbsp%3B

Then%2C%20the%20work%20function%20in%20eV%20of%20the%20photocell%20surface%20is____________.%26nbsp%3B

Answer%3A%201.5

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